have we any mathematicians on board? what doe's 1/84th. mean?I have tried to calculate numerous equations and can't figure it out,what parameters how they using?is it 1" - 84"? a similar discussion was had in an other string.
calculations on a hull plank came up with approx. 3" for a 30' length.that doe's not compute,that would make victory 21" long. don't think so,i've worked it out at 5mm.- 1'0" so where's the 1/84th. come in? at my scale (5mm.-1'0") a plank needs to be 150mm. which comes out at 6" much better scale.the old admiralty plans were drawn at 1/4" to the foot,which works out at 1/75th,? so how is it calculated.?????

The launch scales in at 1/90, as to my dismay, I scaled the oar slots using McKay`s book, he has a 1/192 scale drawing of the launch so X multiplied by 192 divided by 84 = my oar slots. NOT. My launch is 114 mm long, this scales in at about 31ft 4 ins (1/90 ish), pity I didn't check before I started up the chain saw.

So like stedders I too have made a horrendous error of the greatest magnitude on the oar slots, lol stedders

But come to think of it when the carronade truck and wheels scaled in at 1/48 I should of checked first, silly me, but experience is growing

If your wondering why I bothered to scale the oar slots its because they are not all evenly placed and neither are the thwarts, and I cant find anything anywhere about a centre mast so my build isn't having one, just my choice.


Whilst I don`t want to get into anything silly mike I must point out your error in scaling.
When you say
(Therefore: 10ft on the real ship becomes 10 x 254 = 2540 mm.)
This is wrong the equation should read 10 x 12 x 25.4, its 25.4mm to the inch not the foot, No disrespect intended mike

Whilst my brain tends to recoil at the very thought of complex equations and mathematical formulae, I just take it that 1/84 equates to 1 foot of model size to every 84 'real' feet in length.

Thus a figure representing an adult male (let's just ignore the fact that the average male of the period rarely exceeded 5' 'something' and assume that everyone was 6' tall) should come out at... *engages little-used brain cells, takes deep breath* ...around 20mm tall.

84 divided by 6 = 14 (which would relate to 14 miniature crewmen lying in a row, head to toe to make one foot of 'real' measurement.

303mm equals 12"

Thus

303mm divided by 14 equals 21.6mm (being the height of a 6ft male turned into 1/84th scale) - which, ladies and gents sounds about right and should be (within minor deviations) the hieght of the supplied mini's).

*goes for a lie-down and a cold compress*

Quote:

So like stedders I too have made a horrendous error of the greatest magnitude on the oar slots, lol stedders

Does my 'fastest launch in the fleet' have competition (I could always file another set of oar slots you know... )

go to the top of the class

you could always ditch the 10ft and replace it with 34ft i.e 34 x 12 x 25.4 / 84 = 125.7mm and our launch is only 114
so replace the 84 for 90 i.e 34 x 12 x 25.4 / 90 = 115.1

so replace the 90 for 90.9 and we have 114.006 i.e 34 x 12 x 25.4 / 90.9 = 114.006

so our launch is 1/90.9 scale to within 2 decimal points, lol

I think I'll pass on that if you don't mind.

searches desperately for some way of joining in the forum............
gives up & goes back to playing free cell

meh

So I RACKED MY BRAIN for nothing! You're getting the pain killers bill!!!

Hi guys.
Regarding scale. Victory's anchor cable is 24" in circumference (from Anatomy of the Ship). What would that be in mm? I whant to make sure I get the correct twine(As near as dam it)from Cornwall model boats.
Regards
Bob

Nice one wills.
Thanks for that